我有一个具有以下结构的MySQL数据库（节选）：

CREATE TABLE MENU(
    id_menu    TINYINT      UNSIGNED    NOT NULL    AUTO_INCREMENT,name       VARCHAR(50)              NOT NULL,PRIMARY KEY (id_menu)
);

CREATE TABLE OPERATION(
    id_operation    SMALLINT        UNSIGNED    NOT NULL    AUTO_INCREMENT,id_menu         TINYINT         UNSIGNED    NOT NULL,operation       VARCHAR(50)                 NOT NULL,url             VARCHAR(100)                NOT NULL,PRIMARY KEY (id_operation,id_menu)
);

CREATE TABLE operation_role(
    id_operation    SMALLINT    UNSIGNED    NOT NULL,id_menu         TINYINT     UNSIGNED    NOT NULL,role            CHAR(15)                NOT NULL,id_user         BIGINT      UNSIGNED    NOT NULL,id_menu,role,id_user)
);

CREATE TABLE role_user(
    role          CHAR(15)              NOT NULL
    id_user       BIGINT      UNSIGNED  NOT NULL,PRIMARY KEY (role,id_user)
);

-- RELATIONSHIPS

-- 
-- TABLE: OPERATION 
-- Meaning: a MENU has several OPERATION (One to Many relationship)
ALTER TABLE OPERACION ADD CONSTRAINT fk_menu_operacion 
    FOREIGN KEY (id_menu)
    REFERENCES MENU(id_menu);

-- 
-- TABLE: operation_rol 
-- This is the join table for the Many to Many relatioship OPERATION-role_user
ALTER TABLE operation_role ADD CONSTRAINT fk_operation_oprole 
    FOREIGN KEY (id_operation,id_menu)
    REFERENCES OPERATION(id_operation,id_menu);

ALTER TABLE operaciones_rol ADD CONSTRAINT fk_roles_operation 
    FOREIGN KEY (role,id_user)
    REFERENCES role_user(role,id_user);

-- 
-- TABLE: roles_usuario 
-- Meaning: a user can have several roles (One to Many)
ALTER TABLE roles_usuario ADD CONSTRAINT fk_usuario_roles 
    FOREIGN KEY (id_usuario)
    REFERENCES USUARIO(id_usuario);

另外，还有一个USER表，但这并不重要，有了这些表，您可以了解问题的全貌。

如您所见，某些列具有AUTO_INCREMENT将@GeneratedValue(strategy = GenerationType.IDENTITY)在@Entity类中变为的属性。

OPERATION并且role_user由于它们与其他表的关系而具有复合主键，因此我无法更改。由于为Composite
PK，因此映射的类必须具有一个@EmbeddedId带有相应@Embeddable类的。

问题是我需要@GeneratedValue在组合的 “本机”
部分中添加一个PK，例如：OPERATION.id_operation必须具有JPA @GeneratedValue @ EmbeddedId@GeneratedValue并OPERATION.id_menu从中传播。我能正确解释情况吗？MENU.id_menu,butdoes not supportin`

我尝试使用NetBeans 从DataBase 选项的 Entity类 的 “建议”
，但是为具有简单列的标识符（如）的表生成注释，而不为组合对象的表（如）生成注释。 __@GeneratedValue``MENU``OPERATION

所以问题是 我该如何进行映射？ 。更改数据库的结构不是一种选择，因为业务需要，所以要这样做。

任何帮助或指导表示赞赏。提前非常感谢您。

package com.sb.firstjpaexample.pojo;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.SequenceGenerator;
import javax.persistence.Table;
import javax.persistence.TableGenerator;

  @Entity
  @Table(name = "EMPLOYEE")
  public class Employee {

@Id
@TableGenerator(name = "TABLE_GEN",table = "SEQUENCE_TABLE",pkColumnName = "SEQ_NAME",valueColumnName = "SEQ_COUNT",pkColumnValue = "EMP_SEQ",initialValue = 1001,allocationSize = 5)
@GeneratedValue(strategy = GenerationType.TABLE,generator = "TABLE_GEN")
private int employeeId;

@Column
private String employeeName;
@Column
private String designation;
@Column
private double salary;

public int getEmployeeId() {
    return employeeId;
}

public void setEmployeeId(int employeeId) {
    this.employeeId = employeeId;
}

public String getEmployeeName() {
    return employeeName;
}

public void setEmployeeName(String employeeName) {
    this.employeeName = employeeName;
}

public String getDesignation() {
    return designation;
}

public void setDesignation(String designation) {
    this.designation = designation;
}

public double getSalary() {
    return salary;
}

public void setSalary(double salary) {
    this.salary = salary;
}

}

“此POJO在JPA中将初始值为1001，在Hibernate中为1作为初始值”还有一个疑问，如何在此处使用注释设置增量步长在JPA中，当我使用增量策略时，它没有问题，但是增量问题

请帮助我，在此先感谢