在本文中，我们将给您介绍关于解析数据org.json.JSONException时出错：在字符0的输入结束的详细内容，并且为您解答json字符串解析出错的相关问题，此外，我们还将为您提供关于ajax请
在本文中，我们将给您介绍关于解析数据org.json.JSONException时出错：在字符0的输入结束的详细内容，并且为您解答json字符串解析出错的相关问题，此外，我们还将为您提供关于ajax请求json格式的数据，在经过interceptor时出现JSONException、android – org.json.JSON异常：字符0的输入结束、android – 从url解析JSON,异常：解析数据时出错org.json.JSONException：字符115处的未终止数组、android – 解析数据时出错org.json.JSONException：值<？xml的java.lang.String类型无法转换为JSONArray的知识。
本文目录一览：- 解析数据org.json.JSONException时出错：在字符0的输入结束（json字符串解析出错）
- ajax请求json格式的数据，在经过interceptor时出现JSONException
- android – org.json.JSON异常：字符0的输入结束
- android – 从url解析JSON,异常：解析数据时出错org.json.JSONException：字符115处的未终止数组
- android – 解析数据时出错org.json.JSONException：值<？xml的java.lang.String类型无法转换为JSONArray
解析数据org.json.JSONException时出错：在字符0的输入结束（json字符串解析出错）
解析JSON时出现错误。解析数据org.json.JSONException时出错：输入的第0个字符。
错误日志：
04-19 20:51:00.635: E/ViewRootImpl(24857): sendUserActionEvent() mView == null04-19 20:51:00.635: E/ViewRootImpl(24857): sendUserActionEvent() mView == null04-19 20:51:03.320: E/ViewRootImpl(24857): sendUserActionEvent() mView == null04-19 20:51:10.215: E/JSON Parser(24857): Error parsing data org.json.JSONException: End of input at character 0 of 04-19 20:51:35.600: E/ViewRootImpl(24857): sendUserActionEvent() mView == null这是在UserFunction类中调用函数的代码：
pTotalPrice=new double[cartSize]; // store array of totalprice /** To be sent to DB **/ sPID = new String[cartSize]; sProduct = new String[cartSize]; sQuantity = new String[cartSize]; sTotalPrice = new String[cartSize]; if(cartSize >0) { for(int i=0;i<cartSize;i++) { final int counter = i; // Get probuct data from product data arraylist String pID = aController.getProducts(i).getProductId(); sPID[i] = pID; String pName = aController.getProducts(i).getProductName(); sProduct[i] = pName; double pPrice = aController.getProducts(i).getProductPrice(); int pQuantity = aController.getProducts(i).getProductQuantity(); sQuantity[i] = Integer.toString(pQuantity); pTotalPrice[i] = pPrice * pQuantity; sTotalPrice[i] = Double.toString(pTotalPrice[i]); } pFinalPrice -= pTotalPrice[counter];sFinalPrice = Double.toString(pFinalPrice); } protected JSONObject doInBackground(String... args) { UserFunctions userFunction = new UserFunctions(); JSONObject json = userFunction.orderDetails(username, sPID, sProduct, sQuantity, sTotalPrice, Double.toString(pFinalPrice)); Log.d("Button", "Order"); return json; }UserFunction类中的函数
/** * Function store order details **/public JSONObject orderDetails(String username, String[] pid, String[] products, String[] quantity, String[] totalprice, String finalprice) { // Building Parameters List params = new ArrayList(); params.add(new BasicNameValuePair("tag", order_tag)); params.add(new BasicNameValuePair("username", username)); params.add(new BasicNameValuePair("finalpice", finalprice)); for (int i = 0; i < pid.length; i++) { params.add(new BasicNameValuePair("pid[i]", pid[i])); } for (int j = 0; j < products.length; j++) { params.add(new BasicNameValuePair("products[j]", products[j])); } for (int k = 0; k < quantity.length; k++) { params.add(new BasicNameValuePair("quantity[k]", quantity[k])); } for (int l = 0; l < totalprice.length; l++) { params.add(new BasicNameValuePair("totalprice[l]", totalprice[l])); } JSONObject json = jsonParser.getJSONFromUrl(orderURL,params); return json;}Java解析器类：
public class JSONParser {static InputStream is = null;static JSONObject jObj = null;static String json = "";// constructorpublic JSONParser() {}public JSONObject getJSONFromUrl(String url, List params) { // Making HTTP request try { // defaultHttpClient DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); httpPost.setEntity(new UrlEncodedFormEntity(params)); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); is = httpEntity.getContent(); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } try { BufferedReader reader = new BufferedReader(new InputStreamReader( is, "iso-8859-1"), 8); StringBuilder sb = new StringBuilder(); String line = null; while ((line = reader.readLine()) != null) { sb.append(line + "\n"); } is.close(); json = sb.toString(); Log.e("JSON", json); } catch (Exception e) { Log.e("Buffer Error", "Error converting result " + e.toString()); } // try parse the string to a JSON object try { jObj = new JSONObject(json); } catch (JSONException e) { Log.e("JSON Parser", "Error parsing data " + e.toString()); } // return JSON String return jObj;}}这是我的index.php API
else if ($tag == ''order'') { $username = $_POST[''username'']; $finalprice = $_POST[''finalprice'']; $pid = $_POST[''pid'']; $quantity = $_POST[''quantity'']; $totalprice = $_POST[''totalprice'']; $response["successfullypost"] = 1; $response["user"]["username"] = $username; $response["user"]["finalprice"] = $finalprice; $response["user"]["pid"] = $pid; $response["user"]["quantity"] = $quantity; $response["user"]["totalprice"] = $totalprice; echo json_encode($response); $uResult = mysql_query("SELECT * FROM users WHERE username = $username"); $uid = $uResult[''uid'']; $counter = sizeof($pid); for ( $i=0; $i < $counter; $i++) { $db-> orderdetails($uid, $pid[$i], $quantity[$i], $totalprice[$i], $finalprice); }}else { $response["error"] = 3; $response["error_msg"] = "JSON ERROR"; echo json_encode($response);}index.php调用此orderdetails函数
public function orderdetails ($uid, $pid, $quantity, $totalprice, $finalprice) { $pResult = mysql_query("SELECT * FROM products WHERE pid = $pid"); $Product_ID = $pResult[''ProductID'']; $final = mysql_query("INSERT INTO vieworders (uid, ProductID, quantity, $totalprice, finalprice) VALUES (''$uid'', ''$ProductID'', ''$quantity'', ''$totalprice'', ''$finalprice'')");}新的JSON响应。尽管我必须要生产的产品不能显示阵列。为什么JSON标签显示“ i”而不是pid [i]？数量和总价相同
04-20 10:19:31.615: E/ViewRootImpl(20740): sendUserActionEvent() mView == null04-20 10:19:44.505: E/JSON(20740): {"tag":"order","success":0,"error":0,"successfullypost":1,"user":{"username":"zulanawi","finalprice":null,"pid":{"i":"0002"},"quantity":{"k":"3"},"totlaprice":{"l":"32.400000000000006"}}}{"success":0}答案1
小编典典完成！！！在将POST将String数组传递给PHP之后，我得到了答案。
/*** Function store order details**/public JSONObject orderDetails(String username, String[] pid, String[] products, String[] quantity, String[] totalprice, String finalprice) {// Building ParametersList params = new ArrayList();params.add(new BasicNameValuePair("tag", order_tag));params.add(new BasicNameValuePair("username", username));params.add(new BasicNameValuePair("finalpice", finalprice));for (int i = 0; i < pid.length; i++) { params.add(new BasicNameValuePair("pid[]", pid[i]));} for (int j = 0; j < products.length; j++) { params.add(new BasicNameValuePair("products[]", products[j]));}for (int k = 0; k < quantity.length; k++) { params.add(new BasicNameValuePair("quantity[]", quantity[k]));}for (int l = 0; l < totalprice.length; l++) { params.add(new BasicNameValuePair("totalprice[]", totalprice[l]));}JSONObject json = jsonParser.getJSONFromUrl(orderURL,params);return json;}
ajax请求json格式的数据，在经过interceptor时出现JSONException
出现题目描述的问题的原因和对应的解决方法如下：
（1）json中有Date类型的数据，在进行json解析的时候出现改类型不能被正确解析。应该把属性的类定义为java.util.Date;
（2）Action中定义的方法不是要返回前台定义的属性，可是方法的名称是getXxx,jsonplugins把这个方法当作属性用反射的方式调用了，这样就会出行JSONexception。这种情况的解决方法有两种，一种是把方法名不要定义为getXxx,也可以再方法名前加@JSON(serialize=false)。
android – org.json.JSON异常：字符0的输入结束
我正在尝试从android解析json,但我得到了这个奇怪的异常.我的json数据是
{“id”:”1″,”owner”:”1″,”name”:”gravitas”,”description”:”is a fest”,”start_time”:”0000-00-00 00:00:00″,”end_time”:”0000-00-00 00:00:00″,”venue”:”vellore”,”radius”:”10″,”lat”:”11″,”lng”:”11″,”type”:”type”,”ownername”:”dilip”,”noofpolls”:0,”noofquizes”:0,”peopleattending”:0,”result”:true}
在android我做
JSONObject j =new JSONObject(response);
Event pst = gson.fromJson(j.toString(), Event.class);
我明白了：
org.json.JSONException: end of input at character 0 of
它出什么问题了？这是代码……
RestClient client = new RestClient("http://192.168.1.3/services/events/"+eve.getName());
try {
Log.i("MY INFO", "calling boston");
client.Execute(RequestMethod.POST);
} catch (Exception e) {
e.printstacktrace();
}
String response = client.getResponse();
Log.i("MY INFO", response);
GsonBuilder gsonb = new GsonBuilder();
Gson gson = gsonb.create();
Event pst = null;
try {
JSONObject j =new JSONObject(response);
pst = gson.fromJson(j.toString(), Event.class);
} catch (JSONException e) {
// Todo Auto-generated catch block
e.printstacktrace();
}
解决方法:
哎呀！我的坏我本来应该使用GET方法.这个url没有响应POST请求所以我得到了org.json.JSON异常：字符0的输入结束.因为这个我得到了null响应,它产生了异常.
android – 从url解析JSON,异常：解析数据时出错org.json.JSONException：字符115处的未终止数组
我正在解析这个url,我有一个例外,不知道如何跳过它……我只需要获得100个最受欢迎的应用程序的名称.有一个关键的“im：name”,里面有一个键“lebel”,但是我认为它是无效的JsonArray,所以我需要找到通过键“im：name”获取名字的方法…有smb任何想法我该如何解决这个问题？
这是我的AsyncTask.class
public class AsyncTaskParseJson extends AsyncTask<String, String, String> {
String jsonStringUrl = "https://itunes.apple.com/br/RSS/topfreeapplications/limit=100/json";
JSONArray dataJsonArr = null;
@Override
protected void onPreExecute() {}
@Override
protected String doInBackground(String... arg0) {
try {
// instantiate our json parser
JsonParser jParser = new JsonParser();
// get json string from url
JSONObject json = jParser.getJSONFromUrl(jsonStringUrl);
// get the array of users
//HERE I NEED TO CHANGE SOMETHING
dataJsonArr = json.getJSONArray("Feed"); // probably wrong
// loop through all users
for (int i = 0; i < dataJsonArr.length(); i++) {
JSONObject c = dataJsonArr.getJSONObject(i);
// Storing each json item in variable
String name = c.getString("im:name");//probably wrong
}
} catch (JSONException e) {
e.printstacktrace();
}
return null;
}
}
这是日志
09-10 20:04:03.013 18211-18241/com.yuretsrodik.top100apps E/JsonParser.java﹕ Error parsing data org.json.JSONException: Unterminated array at character 115 of {"Feed":{"author":{"name":{"label":"iTunes Store"}, "uri":{"label":"http://www.apple.com/br/itunes/"}}, "entry":[n{"im:name":{"label":"Messenger"}, "im:image":[n{"label":"http://a474.phobos.apple.com/us/r30/Purple4/v4/78/1f/f9/781ff9ea-bf94-5309-4c32-4b901279e54a/mzl.rairyzma.53x53-50.png", "attributes":{"height":"53"}}, n{"label":"http://a990.phobos.apple.com/us/r30/Purple4/v4/78/1f/f9/781ff9ea-bf94-5309-4c32-4b901279e54a/mzl.rairyzma.75x75-65.png", "attributes":{"height":"75"}}, n{"label":"http://a1675.phobos.apple.com/us/r30/Purple4/v4/78/1f/f9/781ff9ea-bf94-5309-4c32-4b901279e54a/mzl.rairyzma.100x100-75.png", "attributes":{"height":"100"}}], "summary":{"label":"lcance instantaneamente as pessoas na sua vida, gratuitamente. O Messenger é como mensagens de texto, mas você não precisa pagar por cada mensagem (funciona com o seu plano de dados). \n\nNão é só para amigos no Facebook: envie mensagens para as pessoas na sua agenda de contatos e basta inserir um número de telefone para adicionar um novo contato.\n\nBate-papos em grupo: crie grupos para as pessoas a quem você mais envia mensagens. Dê um nome a eles, defina fotos para o grupo e os mantenha em um só lugar.\n\nFotos e vÃdeos: grave vÃdeos e tire selfies ou outras fotos diretamente do aplicativo e envie-os com um toque.\n\nLigações gratuitas: fale por quanto tempo quiser, mesmo com pessoas em outros paÃses. (Ligações são gratuitas somente através do Wi-Fi. Do contrário, cobranças de dados padrão são aplicáveis).\n\nMais formas de enviar mensagens: \nDê vida à s suas conversas com as figurinhas. \nVeja uma prévia das suas fotos e vÃdeos no rolo da câmera sem sair da conversa, e escolha as melhores para enviar.\nGrave mensagens de voz quando tiver mais para dizer\n\nRecursos adicionais:\nSaiba quando as pessoas viram suas mensagens.\nEncaminhe mensagens ou fotos para as pessoas que não estavam na conversa.\nProcure pessoas e grupos para entrar em contato com eles rapidamente.\nAtive a localização para que as pessoas saibam que você está nas imediações.\nVeja quem está disponÃvel no Messenger e quem está on-line no Facebook. \nDesative as notificações quando você estiver trabalhando, dormindo ou se precisar dar um tempo.\nFique conectado para nunca perder uma mensagem."}, "im:price":{"label":"Grátis", "attributes":{"amount":"0.00000", "currency":"USD"}}, "im:contentType":{"attributes":{"term":"Application", "label":"Aplicativo"}}, "rights":{"label":"© Facebook, Inc."}, "title":{"label":"Messenger - Facebook, Inc."}, "link":{"attributes":{"rel":"alternate", "type":"text/html", "href":"https://itunes.apple.com/br/app/messenger/id454638411?mt=8&uo=2"}}, "id":{"label":"https://itunes.apple.com/br/app/messenger/id454638411?mt=8&uo=2", "attributes":{"im:id":"454638411", "im:bundleId":"com.facebook.Messenger"}}, "im:artist":{"label":"Facebook, Inc.", "attributes":{"href":"https://itunes.apple.com/br/artist/facebook-inc./id284882218?mt=8&uo=2"}}, "category":{"attributes":{"im:id":"6005", "term":"Social Networking", "scheme":"https://itunes.apple.com/br/genre/ios-redes-sociais/id6005?mt=8&uo=2", "label":"Redes sociais"}}, "im:releaseDate":{"label":"2011-10-19T15:39:30-07:00", "attributes":{"label":"19/10/2011"}}}, n{"im:name":{"label":"WhatsApp Messenger"}, "im:image":[n{"label":"http://a1554.phobos.apple.com/us/r30/Purple1/v4/1f/94/ff/1f94ffd9-159e-a247-2c0f-059f86b6c6c9/mzl.ivmblqpq.53x53-50.png", "attributes":{"height":"53"}}, n{"label":"http://a422.phobos.apple.com/us/r30/Purple1/v4/1f/94/ff/1f94ffd9-159e-a247-2c0f-059f86b6c6c9/mzl.ivmblqpq.75x75-65.png", "attributes":{"height":"75"}}, n{"label":"http://a1251.phobos.apple.com/us/r30/Purple1/v4/1f/94/ff/1f94ffd9-159e-a247-2c0f-059f86b6c6c9/mzl.ivmblqpq.100x100-75.png", "attributes":{"height":"100"}}], "summary":{"label":"O WhatsApp Messenger é um mensageiro para smartphone
09-10 20:04:03.013 18211-18241/com.yuretsrodik.top100apps W/dalvikvm﹕ threadid=11: thread exiting with uncaught exception (group=0x42044e48)
09-10 20:04:03.023 18211-18241/com.yuretsrodik.top100apps E/AndroidRuntime﹕ FATAL EXCEPTION: AsyncTask #1
Process: com.yuretsrodik.top100apps, PID: 18211
java.lang.RuntimeException: An error occured while executing doInBackground()
at android.os.AsyncTask$3.done(AsyncTask.java:300)
at java.util.concurrent.FutureTask.finishCompletion(FutureTask.java:355)
at java.util.concurrent.FutureTask.setException(FutureTask.java:222)
at java.util.concurrent.FutureTask.run(FutureTask.java:242)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)
at java.lang.Thread.run(Thread.java:841)
Caused by: java.lang.NullPointerException
at com.yuretsrodik.top100apps.AsyncTaskParseJson.doInBackground(AsyncTaskParseJson.java:32)
at com.yuretsrodik.top100apps.AsyncTaskParseJson.doInBackground(AsyncTaskParseJson.java:10)
at android.os.AsyncTask$2.call(AsyncTask.java:288)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)
at java.lang.Thread.run(Thread.java:841)
将非常非常感谢帮助!!因为我真的堆叠(
解决方法:
首先,您进行调用将结果转换为名为json的字符串.
然后你必须将字符串转换为Json对象
String json = null;
JSONObject jsonObj = null; JSONObject FeedsObject = null;
json = jParser.getJSONFromUrl(jsonStringUrl);
if (json != null) {
try {
jsonObj = new JSONObject(json);
FeedObject = jsonObj.getJSONObject("Feed");
为了更好地理解,请访问http://json.parser.online.fr/beta/并在那里粘贴您的json数据.
在右边你有一个设置按钮—>显示类型
您可以找到对象,字符串和数组
见下图.你试图获得一个不是数组的对象
android – 解析数据时出错org.json.JSONException：值<？xml的java.lang.String类型无法转换为JSONArray
我正在编写一个打算在
Android设备上运行的应用程序.应用程序通过PHP读取MysqL数据库中的信息,但是当我运行应用程序时,Log cat会提示错误’错误解析数据org.json.JSONException：Value
我得到的代码是从教程中下载的,请耐心等待我已经掌握了一些基本的PHP知识和很少的java知识.我已经测试了PHP脚本,它运行完美,所以我不会费心去附上它.
main.java代码：
package test.an2MysqL;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import org.apache.http.httpentity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.widget.LinearLayout;
import android.widget.TextView;
public class main extends Activity {
/** Called when the activity is first created. */
TextView txt;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
// Create a crude view - this should really be set via the layout resources
// but since its an example saves declaring them in the XML.
LinearLayout rootLayout = new LinearLayout(getApplicationContext());
txt = new TextView(getApplicationContext());
rootLayout.addView(txt);
setContentView(rootLayout);
// Set the text and call the connect function.
txt.setText("Connecting...");
//call the method to run the data retreival
txt.setText(getServerData(KEY_121));
}
public static final String KEY_121 = "http://10.1.1.19/cms/test/android2MysqL/read.PHP"; //i use my real ip here
private String getServerData(String returnString) {
InputStream is = null;
String result = "";
//the data to send
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("country","undefined"));
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(KEY_121);
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
httpentity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag","Error in http connection "+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag","Error converting result "+e.toString());
}
//parse json data
try{
JSONArray jArray = new JSONArray(result);
for(int i=0;i<jArray.length();i++){
JSONObject json_data = jArray.getJSONObject(i);
Log.i("log_tag","id: "+json_data.getInt("id")+
",country: "+json_data.getString("country")+
",documentn: "+json_data.getInt("documentn")
);
//Get an output to the screen
returnString += "\n\t" + jArray.getJSONObject(i);
}
}catch(JSONException e){
Log.e("log_tag","Error parsing data "+e.toString());
}
return returnString;
}
}
我很感激你能给我的任何帮助.
解决方法
正如您对问题的评论中所指出的那样,您的服务器似乎正在返回XML而不是JSON.您只需输出结果即可轻松确认：
}catch(JSONException e){
Log.e("log_tag","Error parsing data "+e.toString());
Log.e("log_tag","Failed data was:\n" + result);
}
如果它是XML,它几乎肯定是必须的,那么你需要让服务器输出JSON,或者你需要解析它发送给你的XML.
关于解析数据org.json.JSONException时出错：在字符0的输入结束和json字符串解析出错的介绍现已完结，谢谢您的耐心阅读，如果想了解更多关于ajax请求json格式的数据，在经过interceptor时出现JSONException、android – org.json.JSON异常：字符0的输入结束、android – 从url解析JSON,异常：解析数据时出错org.json.JSONException：字符115处的未终止数组、android – 解析数据时出错org.json.JSONException：值<？xml的java.lang.String类型无法转换为JSONArray的相关知识，请在本站寻找。
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