在本文中,我们将为您详细介绍汇总各个部门当前员工的title类型的分配数目,结果给出部门编号dept_no、dept_name、其当前员工所有的title以及该类型title对应的数目count的相关
在本文中,我们将为您详细介绍汇总各个部门当前员工的title类型的分配数目,结果给出部门编号dept_no、dept_name、其当前员工所有的title以及该类型title对应的数目count的相关知识,此外,我们还会提供一些关于2022-12-05:部门工资前三高的所有员工。编写一个 SQL 查询找出每个部门中收入前三高的员工 。 +------------+----------+--------+ | Department |、add the push notifications entitlement to your entitlements file、android-table game没有名为title:的列,而在编译时:INSERT INTO game(title,rating,info)VALUES(?,?,?);、Call to undefined function cli_set_process_title,cli_set_process_title 信息 / 选项函数的有用信息。
本文目录一览:- 汇总各个部门当前员工的title类型的分配数目,结果给出部门编号dept_no、dept_name、其当前员工所有的title以及该类型title对应的数目count
- 2022-12-05:部门工资前三高的所有员工。编写一个 SQL 查询找出每个部门中收入前三高的员工 。 +------------+----------+--------+ | Department |
- add the push notifications entitlement to your entitlements file
- android-table game没有名为title:的列,而在编译时:INSERT INTO game(title,rating,info)VALUES(?,?,?);
- Call to undefined function cli_set_process_title,cli_set_process_title 信息 / 选项函数
汇总各个部门当前员工的title类型的分配数目,结果给出部门编号dept_no、dept_name、其当前员工所有的title以及该类型title对应的数目count
`dept_no` char(4) NOT NULL,
`dept_name` varchar(40) NOT NULL,
PRIMARY KEY (`dept_no`));
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE IF NOT EXISTS `titles` (
`emp_no` int(11) NOT NULL,
`title` varchar(50) NOT NULL,
`from_date` date NOT NULL,
`to_date` date DEFAULT NULL);
输入描述:
无
输出描述:
dept_no | dept_name | title | count |
---|---|---|---|
d001 | Marketing | Senior Engineer | 1 |
d001 | Marketing | Staff | 1 |
d002 | Finance | Senior Engineer | 1 |
d003 | Human Resources | Senior Staff | 1 |
d004 | Production | Senior Engineer | 2 |
d005 | Development | Senior Staff | 1 |
d006 | Quality Management | Engineer | 2 |
d006 | Quality Management | Senior Engineer | 1 |
思路:看创建的表以及结果:tiltle是惟一的,需要的是 departments表和title表里面的dept_no,dept_name和title以及title的重复计数,但是departments和title表没有直接关系,
1.连接dept_emp和titles表,判断to_data=‘9999-01-01’ ,d.emp_no=t.emp_no
2.连接department和1操作之后的表,条件dept_no==
3.group by dept_no,title
SELECT de.dept_no, dp.dept_name, t.title, COUNT(t.title) AS count
FROM titles AS t INNER JOIN dept_emp AS de
ON t.emp_no = de.emp_no AND de.to_date = ''9999-01-01'' AND t.to_date = ''9999-01-01''
INNER JOIN departments AS dp
ON de.dept_no = dp.dept_no
GROUP BY de.dept_no, t.title
select dp.dept_no, dp.dept_name, t.title, count(t.title) as count
from titles as t inner join dept_emp as de
on t.emp_no = de.emp_no and t.to_date = ''9999-01-01''and de.to_date = ''9999-01-01''
inner join departments as dp
on de.dept_no = dp.dept_no
group by t.title ,de.dept_no --group by 后面的顺序修改,输出顺序不同,不是输出描述中所需要的表,导致出错不通过
2022-12-05:部门工资前三高的所有员工。编写一个 SQL 查询找出每个部门中收入前三高的员工 。 +------------+----------+--------+ | Department |
2022-12-05:部门工资前三高的所有员工。编写一个 SQL 查询找出每个部门中收入前三高的员工 。 +------------+----------+--------+ | Department | Employee | Salary | +------------+----------+--------+ | IT | Max | 90000 | | IT | Joe | 85000 | | IT | Randy | 85000 | | IT | Will | 70000 | | Sales | Henry | 80000 | | Sales | Sam | 60000 | +------------+----------+--------+
DROP TABLE IF EXISTS `department`;
CREATE TABLE `department` (
`id` int(11) NOT NULL,
`name` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
INSERT INTO `department` VALUES (''1'', ''IT'');
INSERT INTO `department` VALUES (''2'', ''Sales'');
DROP TABLE IF EXISTS `employee`;
CREATE TABLE `employee` (
`id` int(11) NOT NULL,
`name` varchar(255) NOT NULL,
`salary` int(11) NOT NULL,
`department_id` int(11) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
INSERT INTO `employee` VALUES (''1'', ''Joe'', ''85000'', ''1'');
INSERT INTO `employee` VALUES (''2'', ''Henry'', ''80000'', ''2'');
INSERT INTO `employee` VALUES (''3'', ''Sam'', ''60000'', ''2'');
INSERT INTO `employee` VALUES (''4'', ''Max'', ''90000'', ''1'');
INSERT INTO `employee` VALUES (''5'', ''Janet'', ''69000'', ''1'');
INSERT INTO `employee` VALUES (''6'', ''Randy'', ''85000'', ''1'');
INSERT INTO `employee` VALUES (''7'', ''Will'', ''70000'', ''1'');
答案 2022-12-05:
sql 语句如下:
SELECT
d.Name AS ''department'', e1.Name AS ''employee'', e1.salary
FROM
employee e1
JOIN
department d ON e1.department_id = d.id
WHERE
3 > (SELECT
COUNT(DISTINCT e2.salary)
FROM
employee e2
WHERE
e2.salary > e1.salary
AND e1.department_id = e2.department_id
)
;
执行结果如下:
add the push notifications entitlement to your entitlements file
add the push notifications entitlement to your entitlements file
我点击 Fix Issue,这个问题就会消失,然后去其他界面再回来,还是这个问题。
也能正常运行,就是收不到推送
.entitlements 文件双击打开提示:The data couldn’t be read because it isn’t in the correct format.
用记事本打开这个 .entitlements 文件
发现格式不正确
添加一句
<key>aps-environment</key>
android-table game没有名为title:的列,而在编译时:INSERT INTO game(title,rating,info)VALUES(?,?,?);
尝试将项目插入数据库时出现错误.
这是Logcat读取的内容:
android.database.sqlite.sqliteException table game has no column named title: , while compiling: INSERT INTO game(title, rating, info) VALUES (?, ?, ?);
这是我的数据库管理器:
package com.herring.android.finalproject;
import android.content.ContentValues;
import android.content.Context;
import android.database.Cursor;
import android.database.sqlException;
import android.database.sqlite.sqliteDatabase;
import android.database.sqlite.sqliteOpenHelper;
import android.util.Log;
public class GameDataBaseManager {
private DatabaseHelper mDbHelper;
private sqliteDatabase mDb;
private static final String DATABASE_NAME = "data";
private static final int DATABASE_VERSION = 1;
private final Context mCtx;
private static final String GAME_TABLE_NAME = "game";
public static final String KEY_ROWID = "_id";
public static final String KEY_TITLE = "title";
public static final String KEY_BODY = "info";
public static final String KEY_rating = "rating";
private static final String GAME_TABLE_CREATE = "create table " + GAME_TABLE_NAME + " ( " +
KEY_ROWID + " INTEGER PRIMARY KEY AUTOINCREMENT, " +
KEY_TITLE + " TEXT NOT NULL, " +
KEY_BODY + " TEXT NOT NULL, " +
KEY_rating + " NUM NOT NULL );";
public GameDataBaseManager(Context ctx)
{
this.mCtx = ctx;
}
public long addRow(String rowStringOne, String rowStringTwo, float rating)
{
ContentValues values = new ContentValues();
values.put(KEY_TITLE, rowStringOne);
values.put(KEY_BODY, rowStringTwo);
values.put(KEY_rating, rating);
return mDb.insert(GAME_TABLE_NAME, null, values);
}
public void deleteRow(long rowID)
{
try
{
mDb.delete(GAME_TABLE_NAME, KEY_ROWID + " = " + rowID, null);
}
catch(Exception e)
{
Log.e("DB ERROR", e.toString());
e.printstacktrace();
}
}
public GameDataBaseManager open() throws android.database.sqlException
{
mDbHelper = new DatabaseHelper(mCtx);
mDb = mDbHelper.getWritableDatabase();
return this;
}
public void close()
{
mDbHelper.close();
}
public Cursor getAllGames()
{
return mDb.query(GAME_TABLE_NAME, null, null,
null, null, null, null);
}
public Cursor fetchGame(long rowId) throws sqlException
{
Cursor mCursor = mDb.query(true, GAME_TABLE_NAME, new String[]{KEY_ROWID, KEY_TITLE, KEY_BODY, KEY_rating},
KEY_ROWID + "=" + rowId, null, null, null, null, null);
if(mCursor != null)
{
mCursor.movetoFirst();
}
return mCursor;
}
public boolean updateDb(long rowId, String title, String body, String rating)
{
ContentValues args = new ContentValues();
args.put(KEY_TITLE, title);
args.put(KEY_BODY, body);
args.put(KEY_rating, rating);
return mDb.update(GAME_TABLE_NAME, args, KEY_ROWID + " = " + rowId, null) > 0;
}
public class DatabaseHelper extends sqliteOpenHelper {
public DatabaseHelper(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
@Override
public void onCreate(sqliteDatabase db) {
db.execsql(GAME_TABLE_CREATE);
}
@Override
public void onUpgrade(sqliteDatabase db, int oldVersion, int newVersion) {
}
}
}
这是我尝试在其中插入项目的活动:
package com.herring.android.finalproject;
import android.app.Activity;
import android.database.Cursor;
import android.os.Bundle;
import android.widget.ListView;
import android.widget.SimpleCursorAdapter;
public class TopRatedActivity extends Activity {
private Cursor gamesCursor;
private ListView lv;
private GameDataBaseManager mDbHelper;
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
mDbHelper = new GameDataBaseManager(this);
mDbHelper.open();
mDbHelper.addRow("Game", "Info", 0);
setContentView(R.layout.toprated);
fillData();
}
private void fillData()
{
gamesCursor = mDbHelper.getAllGames();
startManagingCursor(gamesCursor);
String[] from = new String[]{GameDataBaseManager.KEY_TITLE};
int[] to = new int[]{R.id.text1};
SimpleCursorAdapter games = new SimpleCursorAdapter(this, R.layout.toprateditem, gamesCursor, from, to);
lv.setAdapter(games);
}
}
任何帮助将不胜感激.
解决方法:
您的数据库中有一个名为“游戏”的表.但是它没有称为“标题”的列.您可以尝试删除整个数据库,然后重新创建它.
Call to undefined function cli_set_process_title,cli_set_process_title 信息 / 选项函数
Fatal error: Uncaught Error: Call to undefined function cli_set_process_title() in /home/wwwroot/es-task/taskServer.php:21 Stack trace: #0 /home/wwwroot/es-task/taskServer.php(155): SwooleTaskServer->__construct() #1 {main} thrown in /home/wwwroot/es-task/taskServer.php on line 21
-
定义和用法
cli_set_process_title - 设置进程标题
- 版本支持
PHP4 PHP5 PHP7 不支持 v5.5.0 + 支持 支持 - 语法
cli_set_process_title( string $title )
cli_set_process_title() 设置进程标题在诸如 top 和 ps 之类的工具中可见。 此功能仅在 CLI 模式下可用。
- 参数
参数 必需的 描述 title 是 新标题 - 返回值
成功时返回 TRUE, 或者在失败时返回 FALSE。
如果操作系统不受支持,将生成 E_WARNING。
- 示例
$title = "My Amazing PHP Script"; $pid = getmypid(); // you can use this to see your process title in ps if (!cli_set_process_title($title)) { echo "Unable to set process title for PID $pid...\n"; exit(1); } else { echo "The process title ''$title'' for PID $pid has been set for your process!\n"; sleep(5); }
- 相关页面
cli_get_process_title() - 返回当前进程的标题
setproctitle() - 设置进程标题
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