对于想了解android–解析数据时出错org.json.JSONException：值的读者，本文将是一篇不可错过的文章，并且为您提供关于AndroidJSON解析错误无法转换为JSONArray、
对于想了解android – 解析数据时出错org.json.JSONException：值<？xml的java.lang.String类型无法转换为JSONArray的读者，本文将是一篇不可错过的文章，并且为您提供关于Android JSON解析错误无法转换为JSONArray、Android json错误com.google.gson.JsonSyntaxException：java.lang.IllegalStateException、android – Gson中的RuntimeException解析JSON：无法调用受保护的java.lang.ClassLoader()而没有args、android – JSONArray无法转换为JSONObject错误的有价值信息。
本文目录一览：- android – 解析数据时出错org.json.JSONException：值<？xml的java.lang.String类型无法转换为JSONArray
- Android JSON解析错误无法转换为JSONArray
- Android json错误com.google.gson.JsonSyntaxException：java.lang.IllegalStateException
- android – Gson中的RuntimeException解析JSON：无法调用受保护的java.lang.ClassLoader()而没有args
- android – JSONArray无法转换为JSONObject错误
android – 解析数据时出错org.json.JSONException：值<？xml的java.lang.String类型无法转换为JSONArray
我得到的代码是从教程中下载的,请耐心等待我已经掌握了一些基本的PHP知识和很少的java知识.我已经测试了PHP脚本,它运行完美,所以我不会费心去附上它.
main.java代码：
package test.an2MysqL;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import org.apache.http.httpentity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.widget.LinearLayout;
import android.widget.TextView;
public class main extends Activity {
/** Called when the activity is first created. */
TextView txt;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
// Create a crude view - this should really be set via the layout resources
// but since its an example saves declaring them in the XML.
LinearLayout rootLayout = new LinearLayout(getApplicationContext());
txt = new TextView(getApplicationContext());
rootLayout.addView(txt);
setContentView(rootLayout);
// Set the text and call the connect function.
txt.setText("Connecting...");
//call the method to run the data retreival
txt.setText(getServerData(KEY_121));
}
public static final String KEY_121 = "http://10.1.1.19/cms/test/android2MysqL/read.PHP"; //i use my real ip here
private String getServerData(String returnString) {
InputStream is = null;
String result = "";
//the data to send
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("country","undefined"));
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(KEY_121);
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
httpentity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag","Error in http connection "+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag","Error converting result "+e.toString());
}
//parse json data
try{
JSONArray jArray = new JSONArray(result);
for(int i=0;i<jArray.length();i++){
JSONObject json_data = jArray.getJSONObject(i);
Log.i("log_tag","id: "+json_data.getInt("id")+
",country: "+json_data.getString("country")+
",documentn: "+json_data.getInt("documentn")
);
//Get an output to the screen
returnString += "\n\t" + jArray.getJSONObject(i);
}
}catch(JSONException e){
Log.e("log_tag","Error parsing data "+e.toString());
}
return returnString;
}
}
我很感激你能给我的任何帮助.
解决方法
}catch(JSONException e){
Log.e("log_tag","Error parsing data "+e.toString());
Log.e("log_tag","Failed data was:\n" + result);
}
如果它是XML,它几乎肯定是必须的,那么你需要让服务器输出JSON,或者你需要解析它发送给你的XML.
Android JSON解析错误无法转换为JSONArray
我是Android开发人员的新手,我正在尝试编写一个程序来解析网站中的一些JSON并将其输出到ListView中.但是,当我运行我的程序时,我收到错误:(有超过7行与此错误相同)
03-31 05:25:14.296 3196-3196/nazilli.tenispark E/Failed: Json parsing
error: Value
{“0″:”2″,”id”:”2″,”1″:”0″,”cid”:”0″,”2″:”1″,”uid”:”1″,”3″:”2017-04-01″,”date”:”2017-04-01″,”4″:”20″,”hour”:”20″}
of type org.json.JSONObject cannot be converted to JSONArray03-31 05:25:14.297 3196-3196/nazilli.tenispark E/Failed: Json parsing error:
Value
{“0″:”3″,”id”:”3″,”1″:”0″,”cid”:”0″,”2″:”1″,”uid”:”1″,”3″:”2017-04-08″,”date”:”2017-04-08″,”4″:”20″,”hour”:”20″}
of type org.json.JSONObject cannot be converted to JSONArray
我试图解析的JSON是：
{“appointments”:[{“0″:”2″,”id”:”2″,”1″:”0″,”cid”:”0″,”2″:”1″,”uid”:”1″,”3″:”2017-04-01″,”date”:”2017-04-01″,”4″:”20″,”hour”:”20″},{“0″:”3″,”id”:”3″,”1″:”0″,”cid”:”0″,”2″:”1″,”uid”:”1″,”3″:”2017-04-08″,”date”:”2017-04-08″,”4″:”20″,”hour”:”20″},{“0″:”4″,”id”:”4″,”1″:”0″,”cid”:”0″,”2″:”1″,”uid”:”1″,”3″:”2017-04-15″,”date”:”2017-04-15″,”4″:”20″,”hour”:”20″},{“0″:”5″,”id”:”5″,”1″:”0″,”cid”:”0″,”2″:”1″,”uid”:”1″,”3″:”2017-04-22″,”date”:”2017-04-22″,”4″:”20″,”hour”:”20″},{“0″:”6″,”id”:”6″,”1″:”0″,”cid”:”0″,”2″:”1″,”uid”:”1″,”3″:”2017-03-24″,”date”:”2017-03-24″,”4″:”17″,”hour”:”17″},{“0″:”7″,”id”:”7″,”1″:”0″,”cid”:”0″,”2″:”1″,”uid”:”1″,”3″:”2017-03-26″,”date”:”2017-03-26″,”4″:”17″,”hour”:”17″},{“0″:”8″,”id”:”8″,”1″:”1″,”cid”:”1″,”2″:”1″,”uid”:”1″,”3″:”2017-03-26″,”date”:”2017-03-26″,”4″:”16″,”hour”:”16″},{“0″:”9″,”id”:”9″,”1″:”2″,”cid”:”2″,”2″:”1″,”uid”:”1″,”3″:”2017-03-26″,”date”:”2017-03-26″,”4″:”15″,”hour”:”15″},{“0″:”10″,”id”:”10″,”1″:”3″,”cid”:”3″,”2″:”1″,”uid”:”1″,”3″:”2017-03-26″,”date”:”2017-03-26″,”4″:”13″,”hour”:”13″}]}
这是我的listview自定义行java
public class adapter_appointment extends ArrayAdapter<String> {
public adapter_appointment(Context context, String[] data){
super(context, R.layout.row_layout, data);
}
@Override
public View getView(int position, View convertView, ViewGroup parent)
{
LayoutInflater inflater = LayoutInflater.from(getContext());
View customView = inflater.inflate(R.layout.row_layout, parent, false);
String all_data = getItem(position);
TextView title = (TextView) customView.findViewById(R.id.title);
//title.setText(all_data.toString());
try {
JSONArray array = new JSONArray(all_data);
JSONObject obj = array.getJSONObject(0);
Log.d("SUCCESS", "JSON Object: " + obj.toString());
if (obj.has("date") && !obj.isNull("date")) {
title.setText(obj.getString("date").toString());
Log.d("SUCCESS", "Date: " + obj.getString("date").toString());
} else {
// Do something
}
} catch (Exception e) {
Log.e("Failed", "Json parsing error: " + e.getMessage());
}
return customView;
}
}
这是json.java
public class my_appointments extends AppCompatActivity {
ListView lv;
InputStream is = null;
String line = null;
String result = null;
String[] data;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_my_appointments);
lv=(ListView) findViewById(R.id.my_appointments);
StrictMode.setThreadPolicy(new StrictMode.ThreadPolicy.Builder().permitNetwork().build());
//Run
getData();
ArrayAdapter adapter = new adapter_appointment(this, data);
lv.setAdapter(adapter);
}
private void getData()
{
try {
URL url = new URL("MY URL");
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setRequestMethod("GET");
is=new BufferedInputStream(con.getInputStream());
//
BufferedReader br = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
while((line=br.readLine()) != null)
{
sb.append(line + "\n");
}
is.close();
result=sb.toString();
//
JSONObject jo = new JSONObject(result);
JSONArray ja = jo.getJSONArray("appointments");
data = new String[ja.length()];
for(int i=0;i<ja.length();i++)
{
jo=ja.getJSONObject(i);
data[i]=jo.toString();
}
}
catch (Exception e)
{
e.printstacktrace();
}
}
}
如果我不解析：
解决方法:
您的所有数据都包含以下数据.如下所示.
alldata={"0":"2","id":"2","1":"0","cid":"0","2":"1","uid":"1","3":"2017-04-01","date":"2017-04-01","4":"20","hour":"20"}
所以每次你的列表项从该约会数组中获取数据.所以alldata变量将根据getItem(position)方法的位置进行更改.
所以,alldata是jsonObject.
所以你应该解析如下,
JSONObject jsonRowData= new JSONObject(allData);
try{
jsonRowData.getString("0");
jsonRowData.getString("id"):
jsonRowData.getString("1"):
jsonRowData.getString("cid"):
jsonRowData.getString("2"):
jsonRowData.getString("uid"):
jsonRowData.getString("3");
jsonRowData.getString("date"):
jsonRowData.getString("4");
}catch(Exception e){
e.printstacktrace();
}
就像你必须打电话.希望能帮助到你
Android json错误com.google.gson.JsonSyntaxException：java.lang.IllegalStateException
我在解析json数据时遇到此错误
Expected BEGIN_ARRAY but was BEGIN_OBJECT at line 1 column 2
我无法找到解决方案.我的json数据是：
{
"user": [
{
"email": "wijden@jerseyrest.com",
"firstName": "Wijden",
"id": "1",
"lastName": "User"
}, {
"email": "user@jerseyrest.com",
"firstName": "Sample",
"id": "2",
"lastName": "User"
}, {
"email": "ingenieur@jerseyrest.com",
"firstName": "Ingenieur",
"id": "3",
"lastName": "User"
}
]
}
这就是我做到的方式：
Type type = new Typetoken<List<WorkItem>>() { }.getType();
List<WorkItem> workitems = (List<WorkItem>) new Gson().fromJson(resultat, type);
如果你能帮助我解决问题,我将不胜感激.提前致谢
解决方法:
为了解析你的JSON,我创建了包装响应的类,即：
public class Response {
@Serializedname("user")
private List<User> userList;
//getters and setters
}
和,
public class User{
@Serializedname("id")
private int id;
@Serializedname("email")
private String email;
@Serializedname("firstName")
private String firstName;
@Serializedname("lastName")
private String lastName;
//getters and setters
}
然后,为了解析您的JSON响应,您只需要：
Gson gson = new Gson();
Response data = gson.fromJson(yourjsonString, Response.class);
然后,您可以非常轻松地访问您的数据,例如：
User user = data.getUserList.get(i);
注意：使用注释@Serializedname对于分离JSON响应中和应用程序中的字段名称很有意义,以便遵循Java命名约定…
android – Gson中的RuntimeException解析JSON：无法调用受保护的java.lang.ClassLoader()而没有args
Gson gson = createGson(); gson.fromJson(objString,myClass);
其中一个保存的字段是Location.不幸的是,很有可能解析保存的数据失败,因为我保存的Location在其mExtras中包含一个mClassLoader,而Gson库无法使用此错误创建ClassLoader：
RuntimeException: Failed to invoke protected java.lang.classLoader() with no args
有谁知道为什么ClassLoader被包含在我的Location的附加内容中,以及它是否应该以JSON表示结尾？
我假设我可以通过单独保存位置对象中的关键字段(例如经度,纬度,高度,时间,精度)来解决这个问题,但如果可能的话,保存位置对象会很好.
我看到有一个ExclusionStrategy对象可用于排除字段,但我不确定是否可以/应该使用它来排除我位置内的额外内容…
仅供参考,这是我的Location对象的JSON数据(经度和纬度改为隐藏我)：
{
<snip>
"lastKNownLocation": {
"mResults": [
0,0
],"mProvider": "gps","mExtras": {
"mParcelledData": {
"mOwnObject": 1,"mObject": 5525040
},"mClassLoader": {
"packages": {}
},"mMap": {},"mHasFds": false,"mFdsKNown": true,"mAllowFds": true
},"mdistance": 0,"mTime": 1354658984849,"mAltitude": 5.199999809265137,"mLongitude": -122.4376,"mLon2": 0,"mLon1": 0,"mLatitude": 37.7577,"mLat1": 0,"mLat2": 0,"mInitialbearing": 0,"mHasspeed": true,"mHasbearing": false,"mHasAltitude": true,"mHasAccuracy": true,"mAccuracy": 16,"mSpeed": 0,"mbearing": 0
},<snip>
}
下面是代码未崩溃时mExtras包含的示例：
"mExtras": {
"mParcelledData": {
"mOwnsNativeParcelObject": true,"mNativePtr": 1544474480
},"mAllowFds": true
}
解决方法
你不能轻易使用@Expose注释,因为它不是你的类;这将需要修改Location的源代码或通过使用jassist在运行时添加它们的相当广泛的过程(参见：http://ayoubelabbassi.blogspot.com/2011/01/how-to-add-annotations-at-runtime-to.html)
查看Location类,我只需创建一个自定义Gson Serializer和Deserializer并完成它.你真正感兴趣的是GPS数据,而不是类本身的内部.您只需使用getter构建包含序列化程序中所需信息的JSON,然后在Deserializer中创建一个新的Location实例,并使用公共setter从提供的JSON中填充信息.
class LocationSerializer implements JsonSerializer<Location>
{
public JsonElement serialize(Location t,Type type,JsonSerializationContext jsc)
{
JsonObject jo = new JsonObject();
jo.addProperty("mProvider",t.getProvider());
jo.addProperty("mAccuracy",t.getAccuracy());
// etc for all the publicly available getters
// for the information you're interested in
// ...
return jo;
}
}
class LocationDeserializer implements JsonDeserializer<Location>
{
public Location deserialize(JsonElement je,JsonDeserializationContext jdc)
throws JsonParseException
{
JsonObject jo = je.getAsJsonObject();
Location l = new Location(jo.getAsJsonPrimitive("mProvider").getAsstring());
l.setAccuracy(jo.getAsJsonPrimitive("mAccuracy").getAsFloat());
// etc,getting and setting all the data
return l;
}
}
现在在您的代码中使用GsonBuilder并注册类：
... GsonBuilder gsonBuilder = new GsonBuilder(); gsonBuilder.registerTypeAdapter(Location.class,new LocationDeserializer()); gsonBuilder.registerTypeAdapter(Location.class,new LocationSerializer()); Gson gson = gsonBuilder.create(); ...
这应该照顾它.
android – JSONArray无法转换为JSONObject错误
在获取json数据时,我收到错误：
JSONArray cannot be converted to JSONObject
生成json的代码：
JSONObject parent = new JSONObject();
DatabaseHandler dbh = new DatabaseHandler(getApplicationContext());
for(int i=0; i < allEds.size(); i++){
String edsText = allEds.get(i).getText().toString();
//spinner = allSpns.get(i);
String spinSelected=allSpns.get(i).getSelectedItem().toString();
try
{
JSONObject json = new JSONObject();
json.put("Id", i);
json.put("FieldName", edsText);
json.put("FieldType",spinSelected);
parent.accumulate("data", json);
}
catch (JSONException e)
{
// Todo Auto-generated catch block
e.printstacktrace();
}
}
Generated json is
{"data":
[{"FieldType":"Account Number","FieldName":"r","Id":0},
{"FieldType":"Net Banking Id","FieldName":"tt","Id":1}
]}
code for json read
------------------
JSONObject jsonObj = new JSONObject(folderStructure);
JSONObject data = jsonObj.getJSONObject("data");
String id = data.getString("Id");
String value = data.getString("FieldName");
Log.d("Item name: ", value);
在阅读上面的json时遇到错误
代码有什么问题吗？
解决方法:
更改
JSONObject data = jsonObj.getJSONObject("data");
至
JSONArray data = jsonObj.getJSONArray("data");
由于数据的值是JsonArray而不是JSONObject.
要获取单个ID和字段名称,您应该遍历此JSONArray,如下所示：
for(int i=0; i<data.length(); i++)
{
JSONObject obj=data.getJSONObject(i);
String id = obj.getString("Id");
String value = obj.getString("FieldName");
Log.d("Item name: ", value);
}
我们今天的关于android – 解析数据时出错org.json.JSONException：值<？xml的java.lang.String类型无法转换为JSONArray的分享就到这里，谢谢您的阅读，如果想了解更多关于Android JSON解析错误无法转换为JSONArray、Android json错误com.google.gson.JsonSyntaxException：java.lang.IllegalStateException、android – Gson中的RuntimeException解析JSON：无法调用受保护的java.lang.ClassLoader()而没有args、android – JSONArray无法转换为JSONObject错误的相关信息，可以在本站进行搜索。
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