最近很多小伙伴都在问java–Android–NewIntent启动特定方法和java启动指定classpath这两个问题，那么本篇文章就来给大家详细解答一下，同时本文还将给你拓展ArrayLista
最近很多小伙伴都在问java – Android – New Intent启动特定方法和java启动指定classpath这两个问题，那么本篇文章就来给大家详细解答一下，同时本文还将给你拓展ArrayList al = new ArrayList（）;有什么区别？和ArrayList al = new ArrayList（0）？、C is for Charlie: New story, new storyboards、C# 泛型 new{ }??? //加new 和不加new 有什么不同? new() 约束、C++ new 关键字的 "new" 学习等相关知识，下面开始了哦！
本文目录一览：- java – Android – New Intent启动特定方法（java启动指定classpath）
- ArrayList al = new ArrayList（）;有什么区别？和ArrayList al = new ArrayList（0）？
- C is for Charlie: New story, new storyboards
- C# 泛型 new{ }??? //加new 和不加new 有什么不同? new() 约束
- C++ new 关键字的 "new" 学习
java – Android – New Intent启动特定方法（java启动指定classpath）
我想启动一个现有的活动,并强制活动在启动后调用特定的方法.这可能吗？
我可以定义一个在我的Intent中创建活动后应该调用的方法吗？
例如,类似于：
Intent intent = new Intent(this, com.app.max.Home.class.myMethod);
解决方法:
不,我认为你不能拥有这样的东西：
Intent intent = new Intent(this, com.app.max.Home.class.method);
但你可以这样做：
Intent intent = new Intent(this, com.app.max.Home.class);
intent.putExtra("methodName","myMethod");
startActivity(intent);
然后在被调用的活动中(你需要启动方法),你可以采取意图并决定调用哪个方法,如下所示：
@Override
protected void onNewIntent(Intent intent) {
super.onNewIntent(intent);
if(intent.getStringExtra("methodName").equals("myMethod")){
mymethod();
}
}
ArrayList al = new ArrayList（）;有什么区别？和ArrayList al = new ArrayList（0）？
ArrayList al = new ArrayList（）;有什么区别？和ArrayList al = new ArrayList（0）？
答案1
小编典典如果您查看API，它将显示ArrayList（）-构造一个初始容量为10的空列表。
ArrayList（int initialCapacity）-构造一个具有指定初始容量的空列表。
C is for Charlie: New story, new storyboards
Hey everyone!
These are some of the storyboards and work in progress images from the second version of the film. Yes, second version! The first version of the film in storyboard form was too long in the end. Not only was it too long, but also some scenes that were required for the film to work and make sense were getting quite complex, in terms of effects and number of characters. So, after drawing probably over 300 storyboards and having edited a film in storyboard form which I really liked, I decided to take a step back.
I took some time off from the film. After I looked at it after two or three weeks, I realized that I need to do something about it. The film was simply too large and too long. Making it shorter was not an option, as I already created a very tight edit in the first place. So, the only option was to rewrite the whole script. A new story from scratch. That was quite hard to accept, but I had to do it or I would be working on the film for far too long.
The new story doesn''t have anything in common with the old one, except for one thing: Charlie. I really like the character, and I really want to animate him, so I kept him. Everything else I changed. The story, the secondary characters, the environment... everything. Charlie''s character changed as well, which I like even more in the new version.
Right now, I am still working on storyboarding the second version of the film, but at this point I think it will work much better. I am really excited about this new version of the film, and I have high hopes that I will not be storyboarding this one for the third time :)
C# 泛型 new{ }??? //加new 和不加new 有什么不同? new() 约束
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace test_20190902_1
{
class Program
{
static void Main(string[] args)
{
HomeController home = new HomeController(); //创建对象 ; 先执行父类构造方法
}
}
public class HomeController : BaseController
{
public HomeController()
{
Console.WriteLine("HomeController类的构造方法"); // 执行顺序 4
}//构造方法
}
public class BaseController : Controller {
public BaseController()
{
Console.WriteLine("BaseController类的构造方法"); // 执行顺序 3
}//构造方法
LogManager logdb = new LogManager(); //先执行属性,再 执行构造
}
//抽象类
public abstract class Controller {}
public class LogManager : DbContext<A> {
public LogManager()
{
Console.WriteLine("LogManager类的构造方法"); // 执行顺序 2
}//构造方法
}
public class DbContext<T> where T : class
{
public DbContext()
{
Console.WriteLine("DbContext类的构造方法"); // 执行顺序 1
}//构造方法
//Virtual方法（虚方法）
public virtual List<T> GetList()
{
return new List<T>();
}
}
//public class DbContext<T> where T : class, new()
//{
// public DbContext() {
// Console.WriteLine("DbContext类的构造方法"); // 执行顺序 1
// }//构造方法
// //Virtual方法（虚方法）
// public virtual List<T> GetList()
// {
// return new List<T>();
// }
//}
public class A { }
//加new 和不加new 有什么不同?
}
//----------
//不包含空构造函数 时候 ,编译不通过 public class A {
public A()
{
}
public A(string str)
{
}
}
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace test_20190902_2
{
class Program
{
static void Main(string[] args)
{
UserManager userdb = new UserManager(); //创建对象
var t = userdb.GetFirst("test"); //继承类可以使用父类方法
}
}
public class A{
int z1 { get; set; }
int z2 { get; set; }
}
public class UserManager : DbContext<A> { }
// T是类型
public class DbContext<T> where T : class
{
public object Db;//用来处理事务多表查询和复杂的操作
public DbContext(){}
public virtual T GetFirst(string str)
{
//return default(T);等同于 return null;
return null;
// Db.Queryable<T>().First(whereExpression);
//return new T(); //T是不同类,要返回不同类的对象时这种方法错误
}
}
}
public static void test<T>(T A, T B) where T : class, new()
{
T temp = new T();
object value;
System.Reflection.PropertyInfo[] obj1_s = A.GetType().GetProperties(); //获得该对象所有属性名
for (int i = 0; i < obj1_s.Length; i++)
{
//temp =A;
value = obj1_s[i].GetValue(A); //获得 第一个对象的 第一个属性值
obj1_s[i].SetValue(temp, value, null); //设置 第二个对象的 第一个属性值
// A = B
value = obj1_s[i].GetValue(B);
obj1_s[i].SetValue(A, value, null); //设置 第二个对象的 第一个属性值
//B =temp
value = obj1_s[i].GetValue(temp);
obj1_s[i].SetValue(B, value, null); //设置 第二个对象的 第一个属性值
}
}
public class ABC
{
int abc { get; set; }
}
void fun3()
{
fun2<ABC>(new ABC());
}
void fun2<T>(T abc) where T : class,new()
{
fun1<T>(abc);
}
void fun1<T>(T abc) where T:class,new()
{
abc = new T();
}
C++ new 关键字的 "new" 学习
以前动态申请内存，申请完后，总要判断指针是否为空，比如
const unsigned int iSize = 1024*1024*1024*1.8;
char *p = new char[iSize];
if(!p)
{
return ; //异常处理
}一直觉得这样没什么问题(现在想来，真是后怕)，今天突然在Effective C++ 上看到，这样写是有大问题的。(当然，malloc/calloc 用上述写法判断返回值，是个好习惯)
C++ 中,new 操作符操作失败，默认是抛出bad_alloc异常(windows 默认的异常处理)的，而不会去判断p == NULL 的情况,也就是说，如果你没有自己的处理new失败的异常处理函数，那么你的程序是肯定要杯具的。
那么，怎么才能让自己的程序稳定(起码不崩溃)呢？
一般有三种做法：
其一就是:
try catch
try
{
char *p = new char[iSize];
}
catch(std::bad_alloc& e)
{
//异常处理
}其二就是自己定义异常处理函数
void Exeception()
{
//异常处理
}
int main(void)
{
set_new_handler(Exeception);
char *p = new char[iSize];
return 0;
}那么new 失败后，程序进入自己的异常处理函数
其三是
char *p = new(std::nothrow) char[iSize]; //如果new 失败，不会抛出异常，二回返回空指针
这样就可以
if(!p)
{
}更多内容详见Effective C++ 条款7
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