在这里，我们将给大家分享关于javaInteger大数据运算的知识，让您更了解java大数运算biginteger的本质，同时也会涉及到如何更有效地1005大数加法——51Nod（javaBigInt
在这里，我们将给大家分享关于java Integer 大数据运算的知识，让您更了解java大数运算biginteger的本质，同时也会涉及到如何更有效地1005 大数加法 ——51Nod（java BigInteger）、Integer Inquiry_hdu_1047(大数).java、Integer.MAX_VALUE和Integer.MIN_VALUE的运算及原理、Integer.valueOf、 Integer.parseInt 、 new Integer的内容。
本文目录一览：- java Integer 大数据运算（java大数运算biginteger）
- 1005 大数加法 ——51Nod（java BigInteger）
- Integer Inquiry_hdu_1047(大数).java
- Integer.MAX_VALUE和Integer.MIN_VALUE的运算及原理
- Integer.valueOf、 Integer.parseInt 、 new Integer
java Integer 大数据运算（java大数运算biginteger）
package com.oracle.demo01;
import java.math.BigDecimal;
import java.math.BigInteger;
public class DemoInteger{
public static void main(String[] args) {
//四则运算：BigInteger 大的数据的运算
BigInteger b1=new BigInteger("100000000000000000000000");
BigInteger b2=new BigInteger("900000000000000000000000");
//加法
System.out.println(b1.add(b2));
//减法
System.out.println(b2.subtract(b1));
//乘法
System.out.println(b1.multiply(b2));
//除法
System.out.println(b2.divide(b1));
//BigDecimal 高精度小数运算
BigDecimal b3=new BigDecimal("0.09");
BigDecimal b4=new BigDecimal("0.01");
//加法
System.out.println(b3.add(b4));
//减法
System.out.println(b3.subtract(b4));
//乘法
System.out.println(b3.multiply(b4));
//除法
System.out.println(b3.divide(b4));
//减法
BigDecimal a1=new BigDecimal("1.0");
BigDecimal a2=new BigDecimal("0.32");
System.out.println(1.0 - 0.32);
System.out.println(a1.subtract(a2));
//乘法
BigDecimal a3=new BigDecimal("1.015");
BigDecimal a4=new BigDecimal("100");
System.out.println(1.015 * 100);
System.out.println(a3.multiply(a4));
//除法
BigDecimal a5=new BigDecimal("1.301");
BigDecimal a6=new BigDecimal("100");
System.out.println(1.301 / 100);
System.out.println(a5.divide(a6));
}
}
.
1005 大数加法 ——51Nod（java BigInteger）
基准时间限制：1 秒 空间限制：131072 KB
给出2个大整数A,B，计算A+B的结果。
Input
第1行：大数A
第2行：大数B
(A,B的长度 <= 10000 需注意：A B有可能为负数）
Output
输出A + B
Input示例
68932147586
468711654886
Output示例
537643802472
思路：
用java的BigInteger来写比较省事（其实就是高精度运算菜的扣脚~唉）
代码：
import java.util.*; import java.math.*; public class Main { /** * @param args */ public static void main(String[] args) { // Todo Auto-generated method stub Scanner in = new Scanner(system.in); BigInteger big1 = in.nextBigInteger(); BigInteger big2 = in.nextBigInteger(); System.out.println(big1.add(big2)); } }
Integer Inquiry_hdu_1047(大数).java
Integer Inquiry
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9376 Accepted Submission(s): 2406
One of the first users of BIT''s new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking varIoUs sums of those numbers.
``This supercomputer is great,'''' remarked Chip. ``I only wish Timothy were here to see these results.'''' (Chip moved to a new apartment,once one became available on the third floor of the Lemon Sky apartments on Third Street.)
``This supercomputer is great,'''' remarked Chip. ``I only wish Timothy were here to see these results.'''' (Chip moved to a new apartment,once one became available on the third floor of the Lemon Sky apartments on Third Street.)
The input will consist of at most 100 lines of text,each of which contains a single VeryLongInteger. Each VeryLongInteger will be 100 or fewer characters in length,and will only contain digits (no VeryLongInteger will be negative).
The final input line will contain a single zero on a line by itself.
The final input line will contain a single zero on a line by itself.
