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md5(str.encode(var1)).hexdigest() 给出十六进制值为 382fbe213f159eecf85facb256f265d0 - 如何知道 var1?

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本文将分享md5(str.encode(var1)).hexdigest()给出十六进制值为382fbe213f159eecf85facb256f265d0-如何知道var1?的详细内容,此外,我们还

本文将分享md5(str.encode(var1)).hexdigest() 给出十六进制值为 382fbe213f159eecf85facb256f265d0 - 如何知道 var1?的详细内容,此外,我们还将为大家带来关于#Leetcode# 515. Find Largest Value in Each Tree Row、821. Shortest Distance to a Character - LeetCode、A Low-Cost Soft Modem Using the Freescale Digital Signal Controller MC56F802x/3x Series、ARCHIVED - A2I25D012NR1, A2I25D012GNR1 2300-2690 MHz, 2.2 W Avg., 28 V Airfast® RF LDM...的相关知识,希望对你有所帮助。

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md5(str.encode(var1)).hexdigest() 给出十六进制值为 382fbe213f159eecf85facb256f265d0 - 如何知道 var1?

md5(str.encode(var1)).hexdigest() 给出十六进制值为 382fbe213f159eecf85facb256f265d0 - 如何知道 var1?

见下面的评论。 需要输出:ws_std

#Leetcode# 515. Find Largest Value in Each Tree Row

#Leetcode# 515. Find Largest Value in Each Tree Row

https://leetcode.com/problems/find-largest-value-in-each-tree-row/

 

You need to find the largest value in each row of a binary tree.

Example:

Input: 

          1
         /         3   2
       / \   \  
      5   3   9 

Output: [1,3,9]

代码:

/**
 * DeFinition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x),left(NULL),right(NULL) {}
 * };
 */
class Solution {
public:
    vector<int> largestValues(TreeNode* root) {
        vector<int> ans;
        if(!root) return ans;
        helper(root,ans,1);
        return ans;
    }
    void helper(TreeNode* root,vector<int>& ans,int depth) {
        if(depth > ans.size()) ans.push_back(root -> val);
        else ans[depth - 1] = max(ans[depth - 1],root -> val);
        if(root -> left) helper(root -> left,depth + 1);
        if(root -> right) helper(root -> right,depth + 1);
    }
};

  今天是不吃宵夜的第二天!!!今天也是被二叉树折磨得死去活来的一天

821. Shortest Distance to a Character - LeetCode

821. Shortest Distance to a Character - LeetCode

Question

821. Shortest Distance to a Character

Solution

思路:遍历字符串 S, 遇到与字符 C 相等就分别向左 / 右计算其他字符与该字符的距离,如果其他字符就是 C 或与目标字符的距离更小的话遍历就终止。

Java 实现:

public int[] shortestToChar(String S, char C) {
    int[] store = new int[S.length()];
    for (int i = 0; i < S.length(); i++) {
        if (S.charAt(i) == C) {
            store[i] = 0;
            left(S, C, store, i);
            right(S, C, store, i);
        }
    }
    return store;
}

void left(String S, char C, int[] store, int target) {
    for (int i = target - 1; i >= 0; i--) {
        if (S.charAt(i) == C) break;
        if (store[i] == 0 || store[i] > target - i) store[i] = target - i;
    }
}

void right(String S, char C, int[] store, int target) {
    for (int i = target + 1; i < S.length(); i++) {
        if (S.charAt(i) == C) break;
        if (store[i] == 0 || store[i] > i - target) store[i] = i - target;
    }
}

A Low-Cost Soft Modem Using the Freescale Digital Signal Controller MC56F802x/3x Series

A Low-Cost Soft Modem Using the Freescale Digital Signal Controller MC56F802x/3x Series

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点击获取完整资源:A Low-Cost Soft Modem Using the Freescale Digital Signal Controller MC56F802x/3x Series

The hardware and software design of a low cost V.22/V.22bis soft modem is presented. The design does not include a traditional telecommunications PCM CODEC (pulse code modulation coder/decoder

点击获取完整资源:A Low-Cost Soft Modem Using the Freescale Digital Signal Controller MC56F802x/3x Series

ARCHIVED - A2I25D012NR1, A2I25D012GNR1 2300-2690 MHz, 2.2 W Avg., 28 V Airfast<sup>®</sup> RF LDM...

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点击获取完整资源:ARCHIVED - A2I25D012NR1, A2I25D012GNR1 2300-2690 MHz, 2.2 W Avg., 28 V Airfast® RF LDMOS Wideband Integrated Power Amplifiers - Data Sheet

ARCHIVED - The A2I25D012N wideband integrated power amplifier is optimized to function with a single multi-band circuit usable from 2300 to 2690 MHz.

点击获取完整资源:ARCHIVED - A2I25D012NR1, A2I25D012GNR1 2300-2690 MHz, 2.2 W Avg., 28 V Airfast® RF LDMOS Wideband Integrated Power Amplifiers - Data Sheet

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