对于iOS开发swift中json解析感兴趣的读者，本文将会是一篇不错的选择，我们将详细介绍swiftuijson，并为您提供关于ios–SwiftyJSON字典解析、ios–Swift：使用Alam
对于iOS开发swift 中json解析感兴趣的读者，本文将会是一篇不错的选择，我们将详细介绍swiftui json，并为您提供关于ios – SwiftyJSON字典解析、ios – Swift：使用Alamofire和SwiftyJSON处理JSON、ios – 在swift 2中解析json对象、ios – 在swift 3中将json解析为数组的有用信息。
本文目录一览：- iOS开发swift 中json解析（swiftui json）
- ios – SwiftyJSON字典解析
- ios – Swift：使用Alamofire和SwiftyJSON处理JSON
- ios – 在swift 2中解析json对象
- ios – 在swift 3中将json解析为数组
iOS开发swift 中json解析（swiftui json）
实现工具类：
import Foundation
public class JSONDecoder {
var value: AnyObject?
///print the description of the JSONDecoder
public var description: String {
return self.print()
}
///convert the value to a String
public var string: String? {
return value as? String
}
///convert the value to an Int
public var integer: Int? {
return value as? Int
}
///convert the value to an UInt
public var unsigned: UInt? {
return value as? UInt
}
///convert the value to a Double
public var double: Double? {
return value as? Double
}
///convert the value to a float
public var float: Float? {
return value as? Float
}
///treat the value as a bool
public var bool: Bool {
if let str = self.string {
let lower = str.lowercaseString
if lower == "true" || lower.toInt() > 0 {
return true
}
} else if let num = self.integer {
return num > 0
} else if let num = self.double {
return num > 0.99
} else if let num = self.float {
return num > 0.99
}
return false
}
//get the value if it is an error
public var error: NSError? {
return value as? NSError
}
//get the value if it is a dictionary
public var dictionary: Dictionary<String,JSONDecoder>? {
return value as? Dictionary<String,JSONDecoder>
}
//get the value if it is an array
public var array: Array<JSONDecoder>? {
return value as? Array<JSONDecoder>
}
//pull the raw values out of an array
public func getArray<T>(inout collect: Array<T>?) {
if let array = value as? Array<JSONDecoder> {
if collect == nil {
collect = Array<T>()
}
for decoder in array {
if let obj = decoder.value as? T {
collect?.append(obj)
}
}
}
}
///pull the raw values out of a dictionary.
public func getDictionary<T>(inout collect: Dictionary<String,T>?) {
if let dictionary = value as? Dictionary<String,JSONDecoder> {
if collect == nil {
collect = Dictionary<String,T>()
}
for (key,decoder) in dictionary {
if let obj = decoder.value as? T {
collect?[key] = obj
}
}
}
}
///the init that converts everything to something nice
public init(_ raw: AnyObject) {
var rawObject: AnyObject = raw
if let data = rawObject as? NSData {
var error: NSError?
var response: AnyObject? = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions(), error: &error)
if error != nil || response == nil {
value = error
return
}
rawObject = response!
}
if let array = rawObject as? NSArray {
var collect = [JSONDecoder]()
for val: AnyObject in array {
collect.append(JSONDecoder(val))
}
value = collect
} else if let dict = rawObject as? NSDictionary {
var collect = Dictionary<String,JSONDecoder>()
for (key,val: AnyObject) in dict {
collect[key as! String] = JSONDecoder(val)
}
value = collect
} else {
value = rawObject
}
}
///Array access support
public subscript(index: Int) -> JSONDecoder {
get {
if let array = self.value as? NSArray {
if array.count > index {
return array[index] as! JSONDecoder
}
}
return JSONDecoder(createError("index: \(index) is greater than array or this is not an Array type."))
}
}
///Dictionary access support
public subscript(key: String) -> JSONDecoder {
get {
if let dict = self.value as? NSDictionary {
if let value: AnyObject = dict[key] {
return value as! JSONDecoder
}
}
return JSONDecoder(createError("key: \(key) does not exist or this is not a Dictionary type"))
}
}
///private method to create an error
func createError(text: String) -> NSError {
return NSError(domain: "JSONJoy", code: 1002, userInfo: [NSLocalizedDescriptionKey: text]);
}
///print the decoder in a JSON format. Helpful for debugging.
public func print() -> String {
if let arr = self.array {
var str = "["
for decoder in arr {
str += decoder.print() + ","
}
str.removeAtIndex(advance(str.endIndex, -1))
return str + "]"
} else if let dict = self.dictionary {
var str = "{"
for (key, decoder) in dict {
str += "\"\(key)\": \(decoder.print()),"
}
str.removeAtIndex(advance(str.endIndex, -1))
return str + "}"
}
if value != nil {
if let str = self.string {
return "\"\(value!)\""
}
return "\(value!)"
}
return ""
}
}
///Implement this protocol on all objects you want to use JSONJoy with
public protocol JSONJoy {
init(_ decoder: JSONDecoder)
}
使用实例：
1.建立数据的发射对象，字段名必须一致啊！列如：
struct UserEntity
{
var userid: Int?
var userName: String?
var name: String?
var true_name: String?
var roleid: Int?
var cellPhone: String?
var telePhone: String?
var statusInfo: String?
var status: Int?
var guide: Bool?
var networkId: Int?
var yxb_authority: Int?
init(){}
init(_ decoder: JSONDecoder) {
userid = decoder["userid"].integer
userName = decoder["userName"].string
name = decoder["name"].string
true_name = decoder["true_name"].string
roleid = decoder["roleid"].integer
cellPhone = decoder["cellPhone"].string
telePhone = decoder["telePhone"].string
statusInfo = decoder["statusInfo"].string
status = decoder["status"].integer
networkId = decoder["networkId"].integer
guide = decoder["guide"].bool
yxb_authority = decoder["yxb_authority"].integer
}
}
struct LoginEntity {
var msgCode: Int?
var message: String?
var field: String?
var data = UserEntity()
init(){}
init(_ decoder: JSONDecoder)
{
msgCode = decoder["msgCode"].integer
message = decoder["message"].string
field = decoder["field"].string
data = UserEntity(decoder["data"])
}
}
2.解析：输出对象data为json串，把String->自定义对象
let data = dataStr.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion:false)
let testJsonStruct:LoginEntity = LoginEntity(JSONDecoder(data!))
ios – SwiftyJSON字典解析
我试图使用
SwiftyJSON来解析服务器中的一些数据.
例如,假设从服务器返回的JSON是：
{
"data":{
"id":"92","name":"harry","username":"Hazza"
},"error":false
}
我想获取用户名字符串,所以为此我使用以下方法获取数据对象：
let data = json["data"].dictionaryValue
然后为了获取我希望能够做的用户名字符串
let username = data["username"].stringValue
但是,这会返回一个错误,说'(String,JSON)没有名为’.stringValue’的成员.
这个看似简单的问题在哪里出错了？
谢谢.
解决方法
你应该做的是：
if let username = json["data"]["username"].string {
println(username)
}
ios – Swift：使用Alamofire和SwiftyJSON处理JSON
这肯定会被问过几次,但我还没有找到正确的答案,尽管我一直很努力.
我使用Alamofire和SwiftyJSON,我的JSON数据看起来像这样：
{
"528" : {
"name" : "Name 1","id" : "528","product_id" : null,"visible" : "0","level" : "2"
},"29" : {
"name" : "Name 2","id" : "29","visible" : "1","level" : "1"
},"173" : {
"name" : "Name 3","id" : "173","143" : {
"name" : "Name 4","id" : "143",
…使用此代码：
Alamofire.request(.GET,dataURL,parameters: nil,encoding: .JSON)
.responseJSON { (request,response,jsonData,error) in
let json = JSON(jsonData!)
println(json)
}
…所以JSON一切都应该没问题
>我如何访问该数据？我的意思是我如何获得名称,ID,product_ids等
>我如何将该数据(名称)放入我的TableViewController？
解决方法
我在我的一个项目中使用了SwiftyJSON和Alamofire.这是我如何使用它.
>创建一个名为APIProtocol的协议.
>使用GET方法设置API类,该方法接受APIProtocol类型的委托.
>设置TableViewController以实现APIProtocol.
>从TableViewController调用API.get()
码
// Step 1
protocol APIProtocol {
func didReceiveResult(results: JSON)
}
// Step 2
func get(path: String,parameters: [String: AnyObject]? = nil,delegate: APIProtocol? = nil){
let url = "\(self.hostname)\(path)"
NSLog("Preparing for GET request to: \(url)")
Alamofire.request(.GET,url,parameters: parameters)
.responseJSON { (req,res,json,error) in
if(error != nil) {
NSLog("GET Error: \(error)")
println(res)
}
else {
var json = JSON(json!)
NSLog("GET Result: \(json)")
// Call delegate if it was passed into the call
if(delegate != nil) {
delegate!.didReceiveResult(json)
}
}
}
}
// Step 3
class ActivityViewController: UITableViewController,APIProtocol {
var activityModelList: NSMutableArray = [] // This is the array that my tableView is using.
...
func didReceiveResult(result: JSON) {
var activities: NSMutableArray = []
NSLog("Activity.didReceiveResult: \(result)")
for (index: String,activity: JSON) in result {
var activityModel = ActivityModel(
id: activity["id"].intValue,message: activity["message"].stringValue
)
activities.addobject(activityModel)
}
// Set our array of new models
activityModelList = activities
// Make sure we are on the main thread,and update the UI.
dispatch_sync(dispatch_get_main_queue(),{
self.refreshControl!.endRefreshing()
self.tableView.reloadData()
})
}
}
// Step 4
override func viewDidLoad() {
MyAPI.get("/activities",delegate: self)
}
ios – 在swift 2中解析json对象
我是iOS和
Swift编程的新手,我正在尝试创建一个解析json对象的方法
我的json如下
{
status : true;
data :[
"url" : "","startDate" : "","endDate" : "",...
]
}
我在swift中的代码是这样的
进口基金会
class SplashResponse {
let STATUS = "status";
let DATA = "data";
let URL = "Url"
let CONTACT_NO = "ContactNo";
let SPLASH_IMAGE = "SplashImage";
let SPLASH_ID = "SplashId";
let TITLE = "Title";
let NO_VIEW = "NoView";
let IS_ACTIVE = "isActive";
let START_DATE = "StartDate";
let END_DATE = "EndDate";
var status : Bool
var url : String
var contactNo : String
var splashImage : String
var splashId : Int
var title : String
var numOfViews : Int
var isActive : Bool
var startDate : String
var endDate : String
init(data : NSDictionary){
status = data[STATUS] as! Bool;
if (status == true) {
if let item = data[DATA] as? [String: AnyObject] {
url = item[URL] as! String;
contactNo = item[CONTACT_NO] as! String;
splashImage = item[SPLASH_IMAGE] as! String;
splashId = item[SPLASH_ID] as! Int;
title = item[TITLE] as! String;
numOfViews = item[NO_VIEW] as! Int;
isActive = item[IS_ACTIVE] as! Bool;
startDate = item[START_DATE] as! String;
endDate = item[END_DATE] as! String;
}
} else {
url = "";
contactNo = "";
splashImage = "";
splashId = -1;
title = "";
numOfViews = -1;
isActive = false;
startDate = "";
endDate = "";
}
}
}
我收到了以下错误
Return from initializer without initializing all stored properties
解决方法
您的问题是,如果if let item = …条件失败,编译器不知道如何初始化您的值.
您有两个选项可用于状态条件,但在真正的分支内部,您创建了一个没有其他分支的新条件,因此编译器正确地抱怨未初始化的存储属性.
我的建议是首先安全地解包数据[DATA]而不制作新的范围,然后使用这些值.
ios – 在swift 3中将json解析为数组
我是
swift的新手,我从请求中得到一个json,但我无法解析.我正在尝试获取json信息并创建在mapkit上使用注释的坐标
下面是我回来的json
{
coord = [
{
islocationactive = 1;
latitude = "37.8037522";
locationid = 1;
locationsubtitle = Danville;
locationtitle = "Schreiner's Home";
longitude = "121.9871216";
},{
islocationactive = 1;
latitude = "37.8191921";
locationid = 2;
locationsubtitle = "Elementary School";
locationtitle = Montair;
longitude = "-122.0071005";
},{
islocationactive = 1;
latitude = "37.8186077";
locationid = 3;
locationsubtitle = "Americas Eats";
locationtitle = "Chaus Restaurant";
longitude = "-121.999046";
},{
islocationactive = 1;
latitude = "37.7789669";
locationid = 4;
locationsubtitle = "Cheer & Dance";
locationtitle = Valley;
longitude = "-121.9829908";
}
] }
我尝试解析的代码就是这个
let task = URLSession.shared.dataTask(with: request as URLRequest){
data,response,error in
//exiting if there is some error
if error != nil{
print("error is \(error)")
return;
}
//parsing the response
do {
//converting resonse to NSDictionary
var teamJSON: NSDictionary!
teamJSON = try JSONSerialization.jsonObject(with: data!,options: .mutableContainers) as? NSDictionary
print(teamJSON)
//getting the JSON array teams from the response
let liquidLocations: NSArray = teamJSON["coord"] as! NSArray
//looping through all the json objects in the array teams
for i in 0 ..< liquidLocations.count{
//getting the data at each index
// let teamId:Int = liquidLocations[i]["locationid"] as! Int!
}
} catch {
print(error)
}
}
//executing the task
task.resume()
但不是我尝试工作.我想得到纬度,经度并在地图上创建一个注释
谢谢您的帮助
解决方法
您可以尝试使用与@Niko Adrianus Yuwono相同的代码,但进行了一些更改,因此您将获得teamid作为整数
do {
let data : NSData = NSData() // change your data variable as you get from webservice response
guard let teamJSON = try NSJSONSerialization.JSONObjectWithData(data,options: []) as? [String: Any],let liquidLocations = teamJSON["coord"] as? [[String: Any]]
else { return }
//looping through all the json objects in the array teams
for i in 0 ..< liquidLocations.count{
let teamId: Int = (liquidLocations[i]["locationid"] as! Nsstring).integerValue
print(teamId)
}
} catch {
print(error)
}
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