在这里，我们将给大家分享关于如何在Linux中打印ios应用程序的共享依赖项的知识，让您更了解linux共享打印机的本质，同时也会涉及到如何更有效地JqueryJsonArray响应未在Div中打印、

在这里，我们将给大家分享关于如何在 Linux 中打印 ios 应用程序的共享依赖项的知识，让您更了解linux共享打印机的本质，同时也会涉及到如何更有效地Jquery Json Array 响应未在 Div 中打印、r - 我如何从嵌套的 tibble 中打印 ggplot 对象，并使用可扩展的行进行响应？、springboot 中打印 sql 语句、sql 查询以从表 A 中打印 id 和 sales 以获取当前年度销售额大于去年的行？的内容。

• 如何在 Linux 中打印 ios 应用程序的共享依赖项（linux共享打印机）
• Jquery Json Array 响应未在 Div 中打印
• r - 我如何从嵌套的 tibble 中打印 ggplot 对象，并使用可扩展的行进行响应？
• springboot 中打印 sql 语句
• sql 查询以从表 A 中打印 id 和 sales 以获取当前年度销售额大于去年的行？

如何在 Linux 中打印 ios 应用程序的共享依赖项（linux共享打印机）

如何解决如何在 Linux 中打印 ios 应用程序的共享依赖项

我想在 linux 脚本中打印 ios 应用程序的共享对象依赖项以进行崩溃解析。

但是我在执行命令时遇到以下错误。 1) ldd ./demoApp.app 不是普通文件 2) ldd ./demoApp.ipa 不是动态可执行文件 3) ldd ./demoApp.app.dSYM/Contents/Resources/DWARF/demoApp 不是动态可执行文件

我应该向 ldd 传递什么参数来打印依赖项。

解决方法

Jquery Json Array 响应未在 Div 中打印

如何解决Jquery Json Array 响应未在 Div 中打印

我正在通过 AJAX 将我的订单 ID 发布到一个 PHP 页面，并且我收到了 json 响应。 我需要在我正在尝试的代码段下方的跟踪订单页面中显示，但出现错误 TypeError: obj.map is not a function. 我试过放 var htmlText = obj.response_data. map(function(o) 仍然出现错误。我如何在我的 DIV 中打印 json 响应 trackorder.PHP

<div class="track-order-response">
</div>
$.ajax({
    url: ''<URL>/trackordercompute.PHP'',type: ''post'',data: order_id,success: function( data ){
    var obj = $.parseJSON( data );
            var htmlText = obj.map(function(o){
              return `
                  <div class="div-conatiner">
                  <p class="p-name"> Transdate: ${o.Transdate}</p>
                  <p class="p-loc"> Transtime: ${o.Transtime}</p>
                  <p class="p-desc"> deliveredTo: ${o.deliveredTo}</p>
                  <p class="p-created"> Remarks: ${o.Remarks}</p>
                 <p class="p-uname"> Location: ${o.Location}</p>
                 </div>
              `;
            });
        $(''.track-order-response'').html( htmlText );
    },error: function( jqXhr,textStatus,errorThrown ){
        console.log( errorThrown );
        $(''.track-order-response'').html( errorThrown );
    }
    });

trackordercompute.PHP

我的 JSON 响应

echo ''
{
    "result": {
    "requested_data": {
    "AuthCode": "XXXX","OrderNumber": "INV374837"
},"response_data": [{
    "Transdate": "11/02/2019","Transtime": "10:15","StatusCode": "POD","deliveredTo": "Rajendran","Remarks": "","Location": "Sharjah"
    },{
    "Transdate": "11/02/2019","Transtime": "08:20","StatusCode": "OD","deliveredTo": "","Remarks": "OUR FOR DELIVERY","Location": "dubai"
    },{
    "Transdate": "10/02/2019","Transtime": "20:10","StatusCode": "AF","Remarks": "ARIVED AT SERVICE CENTER","Transtime": "11:00","StatusCode": "C","Remarks": "Airway Bill Check In","Location": "dubai"
    }]
}
}
'';

解决方法

$.ajax({
                url: ''trackordercompute.php'',type: ''post'',data: order_id,success: function( data ){
                var obj = $.parseJSON( data );
                var htmlData="";
                obj.result.response_data.forEach((o) => {
                    htmlData +=`
                      <div>
                      <p> Transdate: ${o.Transdate}</p>
                      <p> Transtime: ${o.Transtime}</p>
                      <p> deliveredTo: ${o.deliveredTo}</p>
                      <p> Remarks: ${o.Remarks}</p>
                     <p> Location: ${o.Location}</p>
                     </div>
                  `;
                });
                $(''.track-order-response'').html( htmlData );
                },error: function( jqXhr,textStatus,errorThrown ){
                    console.log( errorThrown );
                    $(''.track-order-response'').html( errorThrown );
                }
            });

r - 我如何从嵌套的 tibble 中打印 ggplot 对象，并使用可扩展的行进行响应？

library(dplyr)
library(reactable)
library(ggplot2)

df = iris %>%
  as_tibble() %>%
  nest_by(Species) %>%
  mutate(plot = list(
    ggplot(data,aes(x=Sepal.Length,y=Sepal.Width)) + geom_point() + ggtitle(Species)
  ))

reactable(df %>% select(Species),details = function(index) {
    reactable(df$data[[index]])
  }
)

reactable(df %>% select(Species),details = function(index) {
    print(df$plot[[index]])
  }
)

library(plotly)
library(reactable)
library(ggplot2)
library(dplyr)
reactable(df %>% 
    select(Species),details = function(index) {
 ggplotly(df$plot[[index]])
})

reactable(df %>% select(Species),details = function(index) {
  htmltools::plotTag(df$plot[[index]],alt="plots")
})

logging:
    level:
      com.xxx.com.dao.mapper: DEBUG //包路径为mapper文件包路径

2019-01-24 08:02:14.245 [http-nio-8060-exec-2] DEBUG c.s.a.m.m.U.getUsernameExistSet 159 - ==>  Preparing: SELECT username FROM user_info WHERE username in ( ? , ? , ? ) 
2019-01-24 08:02:14.245 [http-nio-8060-exec-2] DEBUG c.s.a.m.m.U.getUsernameExistSet 159 - ==> Parameters: nike16(String), nike14(String), nike15(String)
2019-01-24 08:02:14.307 [http-nio-8060-exec-2] DEBUG c.s.a.m.m.U.getUsernameExistSet 159 - <==      Total: 0
2019-01-24 08:02:14.323 [http-nio-8060-exec-2] DEBUG c.s.a.m.mapper.UserMapper.saveBatch 159 - ==>  Preparing: INSERT INTO user_info ( username, password, email, telphone, birthday, createTime, updateTime ) values ( ?, ?, ?, ?, ?, ?, ? ) , ( ?, ?, ?, ?, ?, ?, ? ) , ( ?, ?, ?, ?, ?, ?, ? ) 
2019-01-24 08:02:14.323 [http-nio-8060-exec-2] DEBUG c.s.a.m.mapper.UserMapper.saveBatch 159 - ==> Parameters: nike14(String), 4f757a334d69b32b586f3694fbaaa9a9869aee184f98e009b6e02b170f92eb9f(String), hgaha@qq.com(String), null, 2018-03-02 02:01:02.0(Timestamp), 2019-01-24 08:02:14.307(Timestamp), 2019-01-24 08:02:14.307(Timestamp), nike15(String), 18a1c9f3e7a69e3f72ab5d80caea96e5c90f5fada8f9a7e92238dc4242ba03f8(String), hgaha@qq.com(String), null, 2018-03-02 02:01:02.0(Timestamp), 2019-01-24 08:02:14.307(Timestamp), 2019-01-24 08:02:14.307(Timestamp), nike16(String), 5912bd4ff3ae134b15347610b64d9f352dd3c89dd2fb5c495cf4699683b33271(String), hgaha@qq.com(String), null, 2018-03-02 02:01:02.0(Timestamp), 2019-01-24 08:02:14.307(Timestamp), 2019-01-24 08:02:14.307(Timestamp)
2019-01-24 08:02:14.338 [http-nio-8060-exec-2] DEBUG c.s.a.m.mapper.UserMapper.saveBatch 159 - <==    Updates: 3

mybatis
  configuration:
    log-impl: org.apache.ibatis.logging.stdout.StdOutImpl

id,sales,year
1,20k,1991
1,21k,1992
2,30k,1993

CREATE TABLE a(id INT,sales INT,year INT);
INSERT INTO a VALUES(1,20000,1991);
INSERT INTO a VALUES(1,21000,1992);
INSERT INTO a VALUES(2,30000,1993);

select
  b.id,b.sales,b.year
from TableA a
  join TableA b
    on a.id = b.id
   and a.year = b.year-1
where a.sales < b.sales

select a.*
from (select a.*,lag(year) over (partition by id) as prev_year,lag(sales) over (partition by id) as prev_sales
      from a
     ) a
where prev_year = year - 1 and sales > prev_sales;