如何解决Python获取可执行文件的路径？？

我对 Python 编程非常陌生，我已经拼凑了一些代码，希望可以自动重命名特定文件夹中的一堆文件。我需要在没有安装 Python 的计算机上运行这个程序（它没有连接到互联网，我无法在上面安装 Python）所以我使用 auto-py-to- 将 .py 文件转换为 .exe 文件 -可执行程序。 .py 文件在我的笔记本电脑上工作，所以只有当我尝试运行 .exe 文件时才会出现问题。

我在整个代码中使用脚本所在文件夹的路径，因此在脚本的开头，我将文件路径保存为“路径”：

path = os.path.dirname(os.path.realpath(__file__))

但是，当我将 .py 文件转换为 .exe 文件并将该 .exe 文件移动到另一个文件夹时，保存在“路径”变量中的文件路径位于临时文件夹中（可能是文件转换器）。我通过隔离获取文件路径的脚本部分并制作一个 .exe 文件来仅打印该文件路径来测试它。

有没有其他方法可以获取可执行文件的文件路径？我不想将文件路径硬编码到程序中，因为人们经常重新组织该计算机上的文件夹，而我想要这个程序要灵活。

如果上下文需要，这里是其余的代码。谢谢，如果这是一个非常基本的问题，我很抱歉:)

#  This section of code imports the modules used below
import os
import tkinter as tk
from tkinter import simpledialog
from tkinter import messageBox

#  Setting global variables
path = os.path.dirname(os.path.realpath(__file__)) + "/"  # This sets the filepath to the current folder

#  Choosing the dough
dough_input = tk.Tk(className=''Select dough'')
dough_input.geometry(''400x200'')

# This is the code that creates the dough selection Box. Any new types can be added here using the template below:
dough = tk.StringVar()
radiobutton_1 = tk.Radiobutton(dough_input,text=''a'',variable=dough,value="a",tristatevalue=0)
radiobutton_1.pack()
radiobutton_2 = tk.Radiobutton(dough_input,text=''b'',value="b",tristatevalue=0)
radiobutton_2.pack()
radiobutton_3 = tk.Radiobutton(dough_input,text=''c'',value="c",tristatevalue=0)
radiobutton_3.pack()
radiobutton_4 = tk.Radiobutton(dough_input,text=''d'',value="d",tristatevalue=0)
radiobutton_4.pack()


# This section of code saves the dough chosen and closes the pop-up window.
def submitfunction():
    global bread
    bread = dough.get()
    dough_input.destroy()


submit = tk.Button(dough_input,text=''Submit'',command=submitfunction)
submit.pack()

# This section of code triggers the pop-up window for the dough selection.
dough_input.mainloop()

#  Inputting the first number
root = tk.Tk()
root.withdraw()
user_inp = simpledialog.askinteger("Number Input","Input first number:")
i = int(user_inp)

#  Defining the file rename function
def rename():
    global i  # use the variable  "i" defined above (The number that the user inputs)
    for filename in os.listdir(path):  # for each file in the folder specified above do the following
        if ".sur" in filename:
            my_dest = str(bread) + " " + str(i).zfill(4) + ".txt"  # sets the new filename
            my_source = path + filename  # Defines the old filepath to the file
            my_dest = path + my_dest  # Defines the new filepath to the file
            os.rename(my_source,my_dest)  # rename function
            i = i + 1  # advances the program down the list
    messageBox.showinfo("Success","All files have been renamed successfully!")  # confirmation message!


# This function asks the user if the information they''ve input is correct. Once the user clicks "ok" the program runs
# the rename function.
def sanity_check():
    file_list = os.listdir(path)
    j = 0
    for g in file_list:
        if ".txt" in g:
            j += 1

    # This section of code does some calculations and creates a "sanity check" for the user. It takes the number that
    # the user inputted above and sets that as the first number "i". Then it counts the number of files that
    # meets the above criteria and sets that to the number of files. It uses that number of files to calculate the
    # last number in the list. It then concatenates all this information and asks the user to 
    # confirm. If the user presses "ok" then the program
    # proceeds with the rename. If the user presses cancel,the program aborts.

    first_num = i
    num_files = j
    length_files = int(num_files) - 1
    last_file = i + length_files
    last_num = last_file
    check = str(
        "There are " + str(num_files) + " files in this folder. The dough analyzed is " + str(
            dough) + ". The first "
                       "number is " + str(first_num).zfill(
            4) + " and the last number is " + str(
            last_num).zfill(4) + ". Is this correct?")

    # This is the section of code that asks the user to verify the numbers.
    confirmation = messageBox.askokcancel("Sanity Check!",check)
    if confirmation == False:
        messageBox.showerror("","Program Cancelled")
    else:
        rename()


# This is the command that runs the program.
sanity_check()

解决方法

➜  ~ cd /tmp/
➜  /tmp mkdir x
➜  /tmp cd x
➜  x python

Python 3.9.5 (default,May 24 2021,12:50:35)
[GCC 11.1.0] on linux
Type "help","copyright","credits" or "license" for more information.
>>> import os
>>> os.getcwd()
''/tmp/x''
>>> import sys
>>> sys.executable
''/usr/bin/python''
>>>

Private Function GetFiLeversionInfo(ByVal filename As String) As Version
    Return Version.Parse(FiLeversionInfo.GetVersionInfo(filename).FiLeversion)
End Function

Debug.WriteLine(GetFiLeversionInfo("C:\foo\bar\myapp.exe").ToString)

4.2.9.281

DirectoryInfo di = new DirectoryInfo(string.Format(@"{0}..\..\", Application.StartupPath));

di.FullName

DirectoryInfo info = new DirectoryInfo(Application.StartupPath);

String path = info.Parent.Parent.FullName;

string WantedPath = Application.StartupPath.Substring(0,Application.StartupPath.LastIndexOf(@"\"));

DirectoryInfo di = new DirectoryInfo(string.Format(@"{0}..\..\", Application.StartupPath));

di.FullName

DirectoryInfo info = new DirectoryInfo(Application.StartupPath);

String path = info.Parent.Parent.FullName;

string WantedPath = Application.StartupPath.Substring(0,Application.StartupPath.LastIndexOf(@"\"));